# Computation of inductive loads?

Example; a 40 watts flourescent lamp what would be the ampere @ 220 volts supply

### 2 Answers

- 1 decade agoBest Answer
Previous is correct other than that a fluorescent lamp is connected to a choke. Therefore there is PF to be taken into consideration.

Generally, a fluorescent choke has a PF of .8 (nominal) therefore the above answer has to be divided by .8 to get the VA of the circuit.

Answer .2275A.

- 1 decade ago
Well, to solve your example, you could use the following equation:

P=I*V

P=power (in Watts, W)

I= current (in Amperes, A)

V=voltage drop across element (in Volts, V)

For a 40W light bulb at 220V supply, the current is .182A.

Or....

Another important equation is Ohm's Law.

V=I*R

V and I same as above

R is resistance (in Ohms)

Those two equations should get you through most basic circuits. Also, consult Kirchhoff's Loop Laws as needed. Hope this helps. Good luck!

Source(s): Engineering and Physics Student in college; Physics tutor for 5+ years