# Three cards are drawn from a deck of 52 playing cards and not replaced. Find the probability of the following:

a) Getting three jacks

b) Getting an ace, a king, and a queen in order.

c) Getting a club, a spade, and a heart in order

d) Getting three clubs

### 8 Answers

- Amy FLv 51 decade agoBest Answer
OK, for the first one, the chances of the first one being a Jack are 4/52. The chances for the second one are 3/51, and the chances for the third are 2/50. Multiply them together and you get 24/52*51*50, or 1/5525.

For the second, the odds for the first card being an ace are 4/52. The odds of the second one being a king are 4/51, and the odds of the third being a queen are 4/50. So the odds are 64/52*51*50, or 8/16575, or 1/2071.875.

The third question works just like the second one, except there are 13 cards per suit, rather than 4. So the odds for the first card are 13/52, 13/51 for the second and 13/50 for the third. Total odds: 13^3/52*51*50, or 169/10200, or 1/60.355.

The last question works similarly to the first. The odds of the first card being a club are 13/52. The odds for the second are 12/51, and for the third 11/50. Overall odds: 13*12*11/52851*50, or 11/850, or 1/77.(27)repeating.

Source(s): Formulas: none. Calculations: Excel. - 1 decade ago
I'm not really into doing peoples HW for them but this too easy.

a) 4/52 x 3/51 x 2/50 = calculate

b) 4/52 x 4/51 x 4/50 = idk, you'll have to calculate it.

you always times if its an "and" but you add if its an "or"

c)13/52 x 13/51 x 13/50= calculate

d) 13/52 x 12/51 x 11/50= calculate

the club number goes down b/c your not replacing it. You have 13 clubs, you take one out, now you have 12 and 51 cards in all.

I don't feel too bad doing this because you still need to so most of the math. This is too easy hun!

- MaryLv 44 years ago
4 jacks: 4/52 * 3/51 * 2/50 = 1/5525 4 aces, kings, queens: 4/52 * 4/51 * 4/50 = 8/16575 13 clubs, 13 spades, 13 hearts: 13/52 * 13/51 * 13/50 = 169/10200 13 clubs: 13/52 * 12/51 * 11/50 = 11/850 Hope this helps! :)

- rajLv 71 decade ago
a) Getting three jacks 4/52*3/51*2/51

b) Getting an ace, a king, and a queen in order. 4/52*4/51*4/50

c) Getting a club, a spade, and a heart in order13/52*13/51*13/50

d) Getting three clubs 13/52*12/51*11/50

- How do you think about the answers? You can sign in to vote the answer.
- 1 decade ago
Hey, that's four questions! That should be eight points :)

Three jacks would be 1/13 x 1/17 x 1/25

AKQ would be 1/13 x 4/51 x 2/25

CSH would be 1/4 x 13/51 x 13/50

Three clubs would be 1/4 x 4/17 x 11/50

- Modus OperandiLv 61 decade ago
a) = 4/52 * 3/51 * 2/50 = 24 / 132,600 = 3/16575 = 1/5,525

b)4/52 * 4/51 * 4/50 = 64 / 132,600 = 16/33,150

c) 13/52 * 13/51* 13/50 = 2,197/132,600

d) 13/52*12/51*11/50 = 1,716/132,600

- 1 decade ago
a, 4/52 x 3/51 x 2/50

b, 4/52 x 4/51 x 4/50

c, 13/52 x 13/51 x 12/50

d, 13/52 x 12/51 x 11/50