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Two grapes are given equal charges and held apart at a distance of 1.3 m.?
They experience a repulsive force of 2.2 N. Find the magnitude of the charge on each grape.
- nealjkingLv 61 decade agoFavorite Answer
2.2 = F
= k * q^2/(1.3)^2
where k = 8.99e9
q = sqrt(2.2*(1.3^2)/(8.99e9))
= sqrt(22*(1.3^2)/8.99) * e-5
You can do it from here.
- Anonymous4 years ago
relies upon on the correct fee of fee. Then use F = kQq/r^2, the placement F is the repulsive rigidity, ok is the permitivity of air , Q & q are the respective costs and r is the section seperating them.