Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Two grapes are given equal charges and held apart at a distance of 1.3 m.?

They experience a repulsive force of 2.2 N. Find the magnitude of the charge on each grape.

2 Answers

Relevance
  • 1 decade ago
    Favorite Answer

    2.2 = F

    = k*q*q/r^2

    = k * q^2/(1.3)^2

    where k = 8.99e9

    Therefore,

    q = sqrt(2.2*(1.3^2)/(8.99e9))

    = sqrt(22*(1.3^2)/8.99) * e-5

    You can do it from here.

  • Anonymous
    4 years ago

    relies upon on the correct fee of fee. Then use F = kQq/r^2, the placement F is the repulsive rigidity, ok is the permitivity of air , Q & q are the respective costs and r is the section seperating them.

Still have questions? Get your answers by asking now.