How to find the force of a bullet?
A bullet of mass 0.0018 kg initially moving at 486 m/s embeds itself in a large fixed piece of wood and travels 0.54 m before coming to rest. Assume that the acceleration of the bullet is constant.
What force is exerted by the wood on the bullet? (in Newtons)
- 1 decade agoFavorite Answer
There is no force from the wood, it only provides absorption and distribution of the power inherent it the projectile. It is a passive resistance. This resistance can be measured by various means and instruments that take into account target mass. vs impact velocities.....I think.
- CatenaryLv 51 decade ago
F = ma
the mass of the bullet is 0.0018kg
the acceleration is found by solving the following formula for a
v² = u² + 2as
a = (v² - u²)/2s
the final velocity (v) = 0
the initial velocity (u) = 486m/s
the distance (s) = 0.54m
Solve this for a then solve the initial equation.
- 1 decade ago
F=ma. Repeat the mantra...
Bullet. Know m. Check.
Goes from 486 m/s to 0 in 0.54m. Use the V² formula. Know now a. Check.
F=ma. Now know force.