Given the Following reaction Fe(s) + O2(g) --> Fe2O3(s)?
a. How many moles of Fe2O3 can be formed if 2.0 moles of Fe react?
b. How many grams of O2 are needed to react with 2.0 moles of Fe?
c. How many grams of Fe2O3 can be formed if 5.0g of Fe react?
- 1 decade agoFavorite Answer
4Fe(s) + 3O2(g) --> 2Fe2O3(s)
2.0 mol Fe * 2 mol Fe2O3 / 4 mol Fe = 1 mol Fe2O3
(find the mole ratios from the coefficients of the chemical equation)
2.0 mol Fe * 3 mol O2 / 4 mol Fe = 1.5 mol O2
5.0 g Fe * 1 mol Fe / 55.85 g Fe * 2 mol Fe2O3 / 4 mol Fe * 159.7 g Fe2O3 / 1 mol Fe2O3
= 7.15 g
Steps for mass-mass conversions:
mass of known -> moles of known (via the molar mass of known) -> find molar ratio between known and unknown -> mass of unknown (via the molar mass of unknown)
moles of known-> molar ratio between known and unknown-> moles of unknown (answer)
- Dr.ALv 71 decade ago
4 Fe +3 O2 >> 2Fe2O3 is the balanced equation
a. the ratio between Fe and Fe2O3 is 4 : 2. 1.0 mole of Fe2O3 can be formed if 2.0 moles of Fe react
b. the ratio between Fe and O2 is 4 : 3
moles O2 needed = 2.0 x 3 / 4 = 1.5
mass O2 = 1.5 mol x 32 g/mol = 48.0 g
c. Moles Fe = 5.0 g / 55.847 g/mol = 0.090 ( 2 sign. fig.)
The ratio between Fe and Fe2O3 is 4 : 2
Moles Fe2O3 = 0.090 x 2 / 4 = 0.045
Mass Fe2O3 = 0.045 mol x 159.694 g/mol = 7.2 g
- Anonymous1 decade ago
4fe + 3o2 ---> 2fe2o3. - balanced..
ratio of fe and fe2o3 = 4:2
so, i mol. can be formed if two moles react.........
a). 1 mol..
ratio bet. fe and o2 = 4:3
moles. = 2.0 x 3/4 =1.5
1.5 x 32g/mol. = 48....
since o2 = 16 x 16 = 32 x 105 = 48g
ratio - fe- fe2o3 = 4:2.
moles fe2 o3 .= 0.90 x 2/4 = 0.045..
sice fe = 5 /5.847 = 0.0895 = 0.090.
mass = 0.045 x 159.69 of g/mol.
= 7.18605 = 7.2....
i m studying 8th
- 1 decade ago
Balance the equation: 4Fe + 3O2 -> 2Fe2O3
MW of Fe = 55.845 g/mol
MW of O2 = 31.999 g/mol
MW of Fe2O3 = 159.69 g/mol
a) According to the balanced equation, there is 4 mol of Fe for 2 mol of Fe2O3. Therefore:
(2.0 mol Fe)(2 mol Fe2O3 / 4 mol Fe) = 1.0 mol Fe2O3
(2.0 mol Fe)(3 mol O2 / 4 mol Fe) = 1.5 mol O2
(1.5 mol O2)(31.999 g/mol) = 48.0 g O2
(5.0 g Fe) / (55.845 g/mol) = 0.089534 mol Fe
(0.089534 mol Fe)(2 mol Fe2O3 / 4 mol Fe) = 0.044767 mol Fe2O3
(0.044767 mol Fe2O3)(159.69 g/mol) = 7.1488 g Fe2O3
- How do you think about the answers? You can sign in to vote the answer.
- Anonymous4 years ago
If you' trusted' them, (I regard the word 'trust' as a very serious state), then you obviously regarded them very highly. When they destroyed that trust, there treachery really mattered and it hurt. It hurt so much that you really never believed that it could happen, and it's very difficult to ever forget it. You can however in time forgive the friend for being so bloody stupid, but you will never forget the incident. If after this, that friend ever again make the same idiotic mistake, then not only would the friendship be terminated, but you would doubt your own judgment for ever forgiving the sod. The natural action would be to beat his head in, but this action is frowned upon in a lawful society, and you would never get the stain out of the carpet. This makes one very cautious.