How do I find the final volume of this question using both Boyle's law and Charles' law?

Methane gas can be condensed by cooling and increasing the pressure. A 600L sample of methane gas at 25 degrees celsius and 100 kPa is cooled to -20 degrees celsius. In a second step, the gas is compressed until the pressure is quadrupled. What will be the final volume be?

3 Answers

  • Anonymous
    1 decade ago
    Favorite Answer

    P1 x V1/T1=P2 x V2/T2


    T1=25 C = 298.15 K

    P1=100 kPa

    P2= 4 x (P1) = 400 kPa

    T2= -20 C = 253.15 K

    V2= ?


    (600 * 100) / 298.15 = 201.240986

    201.240986 = 400V/253.15

    V=127.36 L

  • Anonymous
    1 decade ago

    You want to use the Combined Gas Law. The formula is:

    P1 x V1 divided by T1 = P2 x V2 divided by T2. Now set up the formula to solve for your unknown:

    V2 = P1 x V1 x T2 divided by T1 x P2. Now list your values:

    P1 = 100 kPa (101.3 kPa - 1 atm. Divide 100 by 101.3

    = .99 atm

    V1 = 600 L

    T1 = 25 C + 273K = 298 Kelvin

    P2 = .99 x 4 = 3.96 atm

    V2 = unknown

    T2 = -20 C + 273 K = 293 K Now plug your values into the


    V2 = .99 atm x 600 L x 293 K divided by 298 K x 3.96 atm

    The atm and K cancel each other out. You are left with:

    .99 x 600 L x 293 divided by 298 x 3.96 = 114042 divided by 1180.08 =147.48 L

  • 1 decade ago

    Volume of a gas is porportional to temperature and inversley porportional to pressure. 25 celcius is 198K and -20 is 153K since zero kelvin is absolute zero where all molecules stop moving and zero celcius is 173K. Kelvin is always the temperature scale used in science except in a few cases.

    in the first part, the volume will decrease by the same factor that temperature decreases and the new volume is 600L*(153K/198K)

    in the second part, volume decreases by the same factor that pressure increases, so divide the above volume by 4., right now, the easiest way to divide by 4 is 600/4=150



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