Anonymous asked in Science & MathematicsChemistry · 1 decade ago

converting mol/L to g/100ml !!!?

hello, i have a problem with converstion:

how do i convert 1.027 x 10^-10 mol/L to g/100 ml???

thanks a lot!

3 Answers

  • 1 decade ago
    Favorite Answer

    You have to know the molar mass of the element or compound to solve this.

    1. You would multiply 1.027x10^-10 mol/L by the molar mass in (g/mol)

    -> check the units, mols will cancel and you'll have g/L.

    2. Then, multiply by 0.1

    -> You use 0.1 because 0.1 L = 100 mL. If you are following units, multiplying the g/L you got in the first step by 0.1 L/ 100 mL will leave you with g/100 mL. Just make sure you don't divide the number by 100 mL... it is a part of your unit

    Summary: 1.027x10^-10 x molar mass x 0.1

    • Mike4 years agoReport

      thank you lady!

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  • 1 decade ago

    okay without knowing what then gram formula weight is the general conversion is

    (1.027 x 10^-10 mol/liter) (grams comp /mol)(0.1liters/100mL)

    the moles cancel, the liters cancel and the units come out as grams of compound per 100 mL

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  • Anonymous
    4 years ago

    Multiply by a conversion factor or conversion factors. Most numbers come with units. A length must have a unit like meters, feet, kilometers, or miles. Speed must have a unit like miles per hour or kilometers per hour. Temperature must have a unit like kelvin, Celsius, or Fahrenheit. Many other units exist for units of area, currency, energy, power, pressure, time, volume, and weight. In this case, you are dealing with mass (g), volume (mL, L), and a very odd one, moles (mol). Moles tell how many atoms or molecules of a particular substance you have just like you can say you have so many dozens of eggs instead of giving the exact number. One mole is approximately 6.02 × 10²³ atoms or molecules. g/100 mL and mol/L are called derived units. They are called this because they are made up of more than one base unit. According to the international system of units, base units include length, mass, time, electric current, temperature, luminous intensity, and amount of substance. Mole is the SI base unit for the amount of substance. Milliliter (mL) and liter (L) are units of volume. There is 1000 mL in one L. Gram is a unit of mass. Now, to convert, you can either use a proportion or multiply by a conversion factor. I find the conversion factor method easier. You need to get rid of grams and replace it with moles and get rid of mL and replace it with L. The mL to L part is easiest. So you have g/100 mL. As you can see mL is being divided. To get rid of it, you must multiply by mL. To get L on the bottom, you must divide by L. The conversion factor will look something like this: mL/L. However, multiplying by mL/L would completely change the value because the fraction does not simplify to be 1. It should be 1000 mL/L because there are 1000 mL in one L. Also, you must account for the 100 next to mL, so the conversion factor now becomes 100000 mL/100 L. Converting to moles is a little bit more tricky, and you need to know the molar mass for the substance you need to convert. This usually includes looking at the periodic table. The mass of a substance given on the periodic table is given in AMU (atomic mass unit) where one AMU is approximately equal to the mass of one neutron or proton. It is also, however, the mass of the substance in grams if there was one mole of it. Thus, 1 AMU = 1 g/mol. Looking at the periodic table, copper (Cu) is 63.546 g/mol, phosphorous (P) is 30.974 g/mol, and oxygen (O) is 15.999 g/mol. The substance you are working with has 3 copper atoms, 2 phosphorous atoms, and 8 oxygen atoms (distribute the 2 to each element the parenthesis). Multiply and add to get the net g/mol of 380.578 g/mol. The problem is, multiplying by grams will not get rid of the grams. Instead, you want to multiply by the inverse of the molar mass, which would be mol/(380.578 g). You just flip the fraction. Grams is successfully canceled and you have moles. (6.1 × 10⁻⁷ g/100 mL) × (100000 mL/100 L) × (mol/(380.578 g)) = 1.60 × 10⁻⁸ mol/L It's easier than it looks.

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