In the xy-plane, line L passes through the origin and is perpendicular to the line 4x+y=k, where k is a ?
In the xy-plane, line L passes through the origin and is perpendicular to the line 4x+y=k, where k is a constant. If the two lines intersect at the point (t, t+1), what is the value of t?
- PeterLLv 41 decade agoBest Answer
slope of line 4x+y=k is -4 so slope of line L is 1/4
Since line L passes thru origin its equation is y=x/4
since they intersect at (t,t+1) then t+1=t/4 from line L equation.
Hence, 3t/4=-1 and t=-4/3 ANSWER
- cattbarfLv 71 decade ago
Let y=Mx be first line.
The second line in slope-intercept format is y=k-4x. So M=1/4 (sneaky, hah).
Now we have y=x/4 and y=k-4x. Since (t,t+1) satisfies both equations, FROM THE FIRST, t+1= t/4 and 3t= -4 or t= -4/3.
In the second, t+1 = k - 4(t), from which k=5t+1. Find k.