In a flask containing 2.00 mol of He, 3.00 mol of Ne, and 5.00 mol of Ar at STP the partial pressure of He is?

Question

In a flask containing 2.00 mol of He, 3.00 mol of Ne, and 5.00 mol of Ar at STP the partial pressure of He is

_____ mm Hg.

Answer 1

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Standard Pressure = 1 atm = 760 mm Hg

According to the law of partial pressures: P(total) = P(He) + P(Ne) + P(Ar)

P(He) = mole fraction of He x total pressure

P(He) = (2/10) x 760 mm Hg = 152mm Hg