Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Anonymous
In a flask containing 2.00 mol of He, 3.00 mol of Ne, and 5.00 mol of Ar at STP the partial pressure of He is?
In a flask containing 2.00 mol of He, 3.00 mol of Ne, and 5.00 mol of Ar at STP the partial pressure of He is
_____ mm Hg.
1 Answer
Relevance
- 1 decade agoFavorite Answer
Standard Pressure = 1 atm = 760 mm Hg
According to the law of partial pressures: P(total) = P(He) + P(Ne) + P(Ar)
P(He) = mole fraction of He x total pressure
P(He) = (2/10) x 760 mm Hg = 152mm Hg
Still have questions? Get your answers by asking now.