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# can you help solve this trig identity?

[sin ^2 x + 2 cosx - 1] / [2 + cosx - cos ^2x] =1/1+sec x

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- vectLv 71 decade agoFavorite Answer
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LHS=

(1-cos^2x+2cosx-1)/(2-cosx)(cosx+1)

=cosx(2-cosx)/(2-cosx)(cosx+1)

=cosx/(cosx+1)

RHS=1/(1+(1/cosx))

=cosx/(1+cosx)=LHS

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