# advance function help?

prove:

tan^2 x - sin^2 x = sin^2 x tan^2 x

thankss alottt

### 1 Answer

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- Seamus OLv 71 decade agoFavorite Answer
LHS = tan² x - sin² x

= [sin² x / cos²x] - sin² x

= [sin² x - sin² x . cos² x] / cos² x [Taking a common denominator]

= [sin² x(1 - cos² x)] / cos² x

= sin² x . [(1 - cos² x) / cos² x]

= sin² x . [sin²x / cos² x] [Because sin² x + cos² x = 1]

= sin² x . tan² x

= RHS

So tan² x - sin² x = sin² x . tan² x

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