How to prove the distance formula of Co-ordinate geometry i.e Pq = √(x2 – x1)2 + (y2 – y1 )2?
Pq = √(x2 – x1)2 + (y2 – y1 )2 is the formula for distance in co-ordinate geometry.How can i prove this ????
- Daniel CLv 41 decade agoBest Answer
To test the answer for yourself, you can substitute in numbers - however, this is not a proof.
The proof is simple - this is an application of Pythagoras' theorem, that a² + b² = c². Here, a is the x difference (i.e. x2 - x1), b is the y difference (i.e. y2 - y1) and c is the actual distance.
For a proof of Pythagoras' Theorem, see http://en.wikipedia.org/wiki/Pythagorean_theorem.
- SusanLv 41 decade ago
This would be difficult to do on this site, but let me get you started.
first: plot 2 points (x1,y1) and (x2,y2) on an x-y axis (doesn't matter where)
then: connect those 2 points. This segment will be a hypotenuse of a right triangle.
now: draw the 2 legs of the right triangle with the above as its hypotenuse.
finally: plug these values into the pythagorean theorem c^2=a^2+b^2
- RetsumLv 61 decade ago
Sketch an x and y-axis. Mark two points P(x, y) ans Q(x, y). Draw a line joining PQ. Now construct a right angled triangle with PQ as the hypotenuse. Apply pythagoras to the triangle noting that one side is (y - y) and the other is x - x.
- ironduke8159Lv 71 decade ago
Just cite the Pythagorean Theorem
- How do you think about the answers? You can sign in to vote the answer.
- PhiloLv 71 decade ago
the line segment connecting the points + a vertical from the one with the highest y coordinate and a horizontal from the one with the smallest x coordinate give you a right triangle. those differences of coordinates give you the length of the vertical and horizontal sides. your proof is just the pythagorean theorem.
- 1 decade ago
insert numbers for the variables- try 1 number for x and 1 number y.
- Anonymous5 years ago
- nozar nazariLv 71 decade ago
Please use Pythegorian theorm.