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# What volume does 22g of CO2 at STP occupy?

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- 1 decade agoFavorite Answer
At STP,

no. of mole of CO2 = Volume of CO2/22.4 in litres

One mole of CO2 = 12 + 16X2

= 44 g

Therefore, no. of mole of CO2 in 22 g = 22/44 = 0.5 mole

Therefore,

0.5 = V/22.4

V = 22.4 X 0.5 = 11.2 litres Ans.

- NorrieLv 71 decade ago
1.0 mol of any gas at STP occupies 22.4L.

CO2 mol mass = C:12 + (2 x O:16) = 44g/mol.

Mass / mol.mass = moles = 22g / 44g/mol = 0.5 moles CO2.

0.5 mol. x 22.4L/mol = 11.2 Litres of CO2 gas at STP.

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