What volume does 22g of CO2 at STP occupy?
- 1 decade agoFavorite Answer
no. of mole of CO2 = Volume of CO2/22.4 in litres
One mole of CO2 = 12 + 16X2
= 44 g
Therefore, no. of mole of CO2 in 22 g = 22/44 = 0.5 mole
0.5 = V/22.4
V = 22.4 X 0.5 = 11.2 litres Ans.
- Gervald FLv 71 decade ago
Half the molar volume, since 22g is half of a mole of CO2.
- NorrieLv 71 decade ago
1.0 mol of any gas at STP occupies 22.4L.
CO2 mol mass = C:12 + (2 x O:16) = 44g/mol.
Mass / mol.mass = moles = 22g / 44g/mol = 0.5 moles CO2.
0.5 mol. x 22.4L/mol = 11.2 Litres of CO2 gas at STP.