Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 decade ago

What volume does 22g of CO2 at STP occupy?

3 Answers

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  • 1 decade ago
    Favorite Answer

    At STP,

    no. of mole of CO2 = Volume of CO2/22.4 in litres

    One mole of CO2 = 12 + 16X2

    = 44 g

    Therefore, no. of mole of CO2 in 22 g = 22/44 = 0.5 mole

    Therefore,

    0.5 = V/22.4

    V = 22.4 X 0.5 = 11.2 litres Ans.

  • 1 decade ago

    Half the molar volume, since 22g is half of a mole of CO2.

  • Norrie
    Lv 7
    1 decade ago

    1.0 mol of any gas at STP occupies 22.4L.

    CO2 mol mass = C:12 + (2 x O:16) = 44g/mol.

    Mass / mol.mass = moles = 22g / 44g/mol = 0.5 moles CO2.

    0.5 mol. x 22.4L/mol = 11.2 Litres of CO2 gas at STP.

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