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# how many atoms of hydrogen are in 67.2L of H2 at STP?

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- AndrewLv 51 decade agoFavorite Answer
1mole of a gas at STP = 22.4L

use a proportion

1/22.4 = x/67.2

multiply both by 67.2

67.2/22.4 = x

3.00=x

there are 3moles of H2 gas

and 2atoms per molecule

3.00moles x 6.022x10^23molecules/mole x 2atoms /molecule = 3.61x10^24 atoms in 67.2 L of H2

alternatively to find moles we could of used the ideal gas law which is

PV nRT

P=pressure

V=volume

n= number of moles

R = ideal gas constant (.0821 L atm / mole K

T = Kelvin temperature

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