What volume is occupied...?

Question

by 8.50 g C2H2 at STP (standard temperature and pressure)? (R=0.08206 L·atm/mol·K)

Answer 1

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moles C2H2 = 8.50 g/ 26.038 g/mol=0.326

there are two ways :

1)

V = nRT / p = 0.326 x 0.08206 x 273 K / 1 atm =7.30 L

2)

at STP one mole of any gas occupies 22.4 L

V = 22.4 x 0.326 = 7.30 L