What volume is occupied...?

by 8.50 g C2H2 at STP (standard temperature and pressure)? (R=0.08206 L·atm/mol·K)

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  • Dr.A
    Lv 7
    1 decade ago
    Favorite Answer

    moles C2H2 = 8.50 g/ 26.038 g/mol=0.326

    there are two ways :

    1)

    V = nRT / p = 0.326 x 0.08206 x 273 K / 1 atm =7.30 L

    2)

    at STP one mole of any gas occupies 22.4 L

    V = 22.4 x 0.326 = 7.30 L

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