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Can someone help me with a question in Chemistry?
How many moles of oxygen is available for a combustion reaction in a volume of 5.6L at STP?
What volume is occupied by 0.024mol of CO2 gas at STP?
- 1 decade agoFavorite Answer
At STP (standard temperature and pressure, 1 atm and 273 K), an ideal gas takes up 22.4 L for each mole. In 5.6 L of oxygen (which we assume to be an ideal gas), we have (5.6 L)/(22.4 mol/L) moles of oxygen = 0.25 mol of oxygen.
Similarly, for CO2, 22.4 L/mol x 0.024 mol = 0.54 L.Source(s): Masters in Chemistry