How many moles of oxygen is available for a combustion reaction in a volume of 5.6L at STP?
- 10 years agoFavorite Answer
In STP, ideal gas has 22.4 mol/1L.
5.6 L * 22.4 mol/1 L = 125.44 mols O2
With sig fig, 1.3 x 10^2 mols O2
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