given the first and last term; arethmetic series?
the terms A=3, T6=11.
you need to find the sum of each arthmetic series
- Apratim RLv 610 years agoFavorite Answer
Recall that for an arithmetic progression (AP) with initial term a and common difference d, the n-th term is t(n) = a + (n-1) d.
Here a = 3, n = 6, so
11 = t(6) = a + (6-1) d = 3 + 5 d, so d = 8/5 = 1.6.
So t(n) = a(1) + (n-1) d = 3 + 1.6 (n-1) = 1.6 n + 1.4.