Anonymous asked in Science & MathematicsChemistry · 9 years ago

what is the volume of oxygen gas at STP if it had a volume of 5L at 103kPa and 300 K?

thank you


stp = molar volume = 22.4L/mol

3 Answers

  • 9 years ago
    Favorite Answer

    STP = 273K ans 101.3kPa

    Use equation:

    P1V1/T1 = P2V2/T2

    101.3 *V1 / 273 = 103*5/300

    101.3*V1* 300 = 273*103*5

    V1 = 140,595 / 30,390

    V1 = 4.6 litres.

    Note: stp = molar volume = 22.4L/mol is not required in this problem - unless you really want to make your life complicated.

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  • 9 years ago

    I think you simply want to do a ratio problem.

    P1V1/T1 = P2V2/T2

    You have all the values for P1,V1 and T1.

    You know the standard pressure and temperature, which will be P2 and T2, so solve for the new volume, V2.

    Just make sure your units are consistent.

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  • Anonymous
    9 years ago

    We can't exactly make sense of your question. Would you describe with more information? Thanks.

    Source(s): Comprehension.
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