Trigonometric Identities #3!?

1/secx + sinx/cotx = 1/cosx

Please & thank you!

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  • 9 years ago
    Favorite Answer

    LHS

    = 1/sec x + sin x/cot x

    = cos x + sin x tan x

    = cos x + sin x * sin x / cos x

    = cos x/cos x * cos x + sin x * sin x / cos x

    = (cos^2 x + sin^2 x ) / cos x

    = 1 / cos x

    = RHS

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  • 9 years ago

    Left side= 1/secx+sinx/cosx

    1/1/cosx+sinx/cosx

    1* cosx/1+sinx/cosx

    cosx+sinx/cosx

    cosx/cosx+sinx/cosx

    sinxcosx/cosx

    =sinx

    Right side = 1/cosx

    secx

    secx=sinx/sinx

    secx=sinx

    //QED LS=RS

    Its only a guess.

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  • 9 years ago

    I'm not sure what the directions is to do for this problem?.?.?.

    But this simplifies to...

    cosx+tanx=secx

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