A 2.7 KΩ resistor dissipates 50 mW of power. What is the voltage across the resistor ?

A 2.7 Kilo-Ohm resistor dissipates 50 mW of power. What is the voltage across the resistor?

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  • TBT
    Lv 7
    9 years ago
    Best Answer

    Power = VI

    and V =IR => I = V/R

    Power = V * V/ R

    50 * 10^-3 = V^2 / 2.7*10^3

    V^2 = 135

    V= 11.62 volt ---answer

    Assuming DC circuit.

    Source(s): My brain (Prof TBT)
  • 9 years ago

    Voltage= Square Root of ( Power X Resistance)

  • KMcG
    Lv 7
    9 years ago

    Ok Ohm's law current is equal to voltage times resistance.

    And Power (watts) is equal to voltage times current.

    There that's every thing you need to know to figure it out.

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