A 2.7 KΩ resistor dissipates 50 mW of power. What is the voltage across the resistor ?
A 2.7 Kilo-Ohm resistor dissipates 50 mW of power. What is the voltage across the resistor?
- TBTLv 79 years agoBest Answer
Power = VI
and V =IR => I = V/R
Power = V * V/ R
50 * 10^-3 = V^2 / 2.7*10^3
V^2 = 135
V= 11.62 volt ---answer
Assuming DC circuit.Source(s): My brain (Prof TBT)
- 9 years ago
Voltage= Square Root of ( Power X Resistance)
- KMcGLv 79 years ago
Ok Ohm's law current is equal to voltage times resistance.
And Power (watts) is equal to voltage times current.
There that's every thing you need to know to figure it out.