# I don't understand this problem and i really need help with it?

Let f and g be two functions defined by

f(x) = x + 4

g(x)= x^2 - 49

For any real number x

Find all values of x that are not in the domain of the function of f/g

### 4 Answers

- Anonymous9 years agoFavorite Answer
If (f/g)(x) = f(x)/g(x)..

(f/g)(x)

= (x+ 4)/(x² - 49) where x ≠ ±7

I hope this helps!

Source(s): Knowledge - Anonymous9 years ago
If i am interpreting this correctly they want you to divide f(x) by g(x) so

(x+4)/(x^2-49)

the values of x that are not in the domain of the function will be the values for which the denominator is equal to 0. Factoring the denominator you get (x+7)(x-7)

therefore the two values of x that are not in the domain of the function are 7 and -7

- Anonymous9 years ago
f/g would be (x+4)/(x^2 -49); anything that made the denominator 0 would not be in the domain, since you can't divide by 0. Factor the denominator and set to 0; (x+7)(x-7)=0; x =-7 or 7. These are the values that are not in the domain of f/g.

- 9 years ago
Whenever x=7 then g=0 and f/g is undefined so the value x=7 is not in the domain.

Source(s): 2 years math