I don't understand this problem and i really need help with it?

Let f and g be two functions defined by

f(x) = x + 4

g(x)= x^2 - 49

For any real number x

Find all values of x that are not in the domain of the function of f/g

4 Answers

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  • Anonymous
    9 years ago
    Favorite Answer

    If (f/g)(x) = f(x)/g(x)..

    (f/g)(x)

    = (x+ 4)/(x² - 49) where x ≠ ±7

    I hope this helps!

    Source(s): Knowledge
  • Anonymous
    9 years ago

    If i am interpreting this correctly they want you to divide f(x) by g(x) so

    (x+4)/(x^2-49)

    the values of x that are not in the domain of the function will be the values for which the denominator is equal to 0. Factoring the denominator you get (x+7)(x-7)

    therefore the two values of x that are not in the domain of the function are 7 and -7

  • Anonymous
    9 years ago

    f/g would be (x+4)/(x^2 -49); anything that made the denominator 0 would not be in the domain, since you can't divide by 0. Factor the denominator and set to 0; (x+7)(x-7)=0; x =-7 or 7. These are the values that are not in the domain of f/g.

  • 9 years ago

    Whenever x=7 then g=0 and f/g is undefined so the value x=7 is not in the domain.

    Source(s): 2 years math
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