Anonymous
Anonymous asked in Science & MathematicsBiology · 9 years ago

# If 650 out of 1000 alleles are dominant, calculate the frequencies of the dominant and recessive alleles?

in the population

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Frequency of alleles within a population:

Dominant allele frequency + recessive allele frequency = 1

The equation is written as "p+q=1," where p is the frequency of the dominant allele, and q is the frequency of the recessive allele.

Frequencies are usually written in decimals.

Dominant allele frequency = 650/1000

= 0.65

Therefore, p= 0.65

p+q = 1

0.65+q = 1

Therefore, q is equal to 0.35,

In conclusion, the frequency of the dominant allele is 0.65, while the frequency of the recessive allele is 0.35.

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• First calculate the genotype frequencies via dividing variety of persons via inhabitants entire: AA: 1469/1612=.911 Aa: 138/1612=.086 aa: 5/1612=.003 Now calculate allele frequency: it quite is accomplished via taking the genotype frequency of the two homozygote and including it a million/2 the genotype frequency of the heterozygote. the explanation why is that the heterozygote has the two alleles. .911+ (.5(.086))=.954 is the frequency of A a million-.954=.046 is the frequency of a.

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