If 650 out of 1000 alleles are dominant, calculate the frequencies of the dominant and recessive alleles?
in the population
- ReligulousLv 69 years agoFavorite Answer
Frequency of alleles within a population:
Dominant allele frequency + recessive allele frequency = 1
The equation is written as "p+q=1," where p is the frequency of the dominant allele, and q is the frequency of the recessive allele.
Frequencies are usually written in decimals.
Dominant allele frequency = 650/1000
Therefore, p= 0.65
p+q = 1
0.65+q = 1
Therefore, q is equal to 0.35,
In conclusion, the frequency of the dominant allele is 0.65, while the frequency of the recessive allele is 0.35.
- 4 years ago
First calculate the genotype frequencies via dividing variety of persons via inhabitants entire: AA: 1469/1612=.911 Aa: 138/1612=.086 aa: 5/1612=.003 Now calculate allele frequency: it quite is accomplished via taking the genotype frequency of the two homozygote and including it a million/2 the genotype frequency of the heterozygote. the explanation why is that the heterozygote has the two alleles. .911+ (.5(.086))=.954 is the frequency of A a million-.954=.046 is the frequency of a.