A 41.1 mL sample of H2 at STP would contain how many grams of hydrogen?

a. 0.00183 g

b. 3.70 g

c. 1.83 g

d. 110 g

e. 0.0037 g

1 Answer

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  • Lexi R
    Lv 7
    8 years ago
    Favorite Answer

    At STP 1 mole of any ideal gas occupies a volume of 22.4 L

    So

    moles gas at STP = volume (L) / 22.4 L/mol

    moles H2 = 0.0411 L / 22.4 L/mol

    = 0.00183 mol

    mass = molar mass x moles

    = 2.016 g/mol x 0.00183 mol

    = 0.00370 g

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