Anonymous
Anonymous asked in Science & MathematicsMathematics · 8 years ago

Solve for x :ap^(bx+c) -d =0?

solve for x: ap^(bx+c) -d =0

when p; a; d > 0; b cannot equal 0; ceR

2 Answers

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  • 8 years ago
    Best Answer

    ap^(bx + c) - d = 0

    ap^(bx + c) = d

    p^(bx + c) = d/a

    log (base p) of (d/a) = bx + c

    bx = (log (base p) of (d/a)) - c

    x = ((log (base p) of (d/a)) - c) / b

  • theron
    Lv 4
    3 years ago

    difficulty a million: Use the quadratic formulation. x = [ -b ± ?(b² - 4ac) ] / 2a a = a million b = a million c = -3 x = [ -a million ± ?(a million² - 4(a million)(-3)) ] / 2 x = [ -a million ± ?(13) ] / 2 answer: x = -a million/2 ± (?13)/2 difficulty A: Quadratic formulation back with a = 5, b = -4, c = a million. you attempt this one on your man or woman... difficulty B: 9x² = 14 x² = 14/9 x = ± ?(14/9) x = ± (?14) / 3 difficulty C: Take the sq. root of the two sides: x + 5 = ± ?3 x = -5 ± ?3 difficulty D; Quadratic formulation difficulty E: See difficulty a million.

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