Determine whether the following statement and it's negation are true:
∀x ∈ℝ, ∃y ∈ℝ such that xy=2.
for all x in set of real numbers, there exists y in set of real numbers such that xy=2.
just making sure i'm understanding the symbols right.
not sure where to go from here.
is the question asking if any real number x by static number y would = 2?
- Iggy RockoLv 78 years agoFavorite Answer
The statement is false if the negation is true, namely
∃x∈ℝ such that ∀y∈ℝ, xy ╪ 2.
This negation is true. Let x = 0. There is no real y that yields xy = 2.