What volume, in liters, of H2 at STP is released when 8.81g of Mg reacts?

Mg metal reacts with HCL to produce hydrogen gas.

Mg(s)+2HCl9(aq)->MgCl2(aq)+H2(g)

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  • 7 years ago
    Best Answer

    Mg + 2 HCl → MgCl2 + H2

    (8.81 g Mg) / (24.30506 g Mg/mol) x (1/1) x (22.414 L/mol) = 8.12 L H2

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