Cal 1 Limits Question: as x->0 ?
I don't understand how evaluate this! Please explain :)
lim x->0 (cot(5x)) / (cot(7x))
10 pts best answer
**sorry i should have specified! without derivatives please, we haven't covered them yet!
- MelvynLv 78 years ago
cos[5x] / Sin[5x] * Sin [7x]/Cos[7x] = (cos5x sin[7x]) /( sin[5x] cos[7x])
this is obviously 0/0 when x=0 so use L'Hospitals rule
(7Cos[5x]Cos[7x]-5Sin[5x]sin[7x])/(5cos [5x]cos[7x]-7sin[5x]sin [7x])
evaluated at x=0 ,7 / 5 = 1.4