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Sin2x/(sinx) - cos2x/(cos x)?
How do u proof that LHS=RHS
- 9 years agoFavorite Answer
Since cos^2(x)=(1+cos2x)/2 so we obtain cos2x=2cos^(x)-1 also we know sin2x=2sin(x)cos(x) now if we put these things in what u have writen we will have [(2sin(x)cos(x)]/sin(x) - (2cos^(x)-1)/cos(x) = 2cos(x)-2cos(x)+ (1/cos(x))=sec(x)Source(s): Me
- Sridhar RLv 69 years ago
Only one side of equation is given
any how you can simplify this as follows
sin 2x / sin x - cos 2x / cos x
Taking LCM we get
(sin2x cosx - cos 2x sin x) /sin x cos x
sin(2x -x) / sinx cos x using Sin (A-B) sinAcosB - cosAsinB
sin x/ sin x cos x = 1/cos x