Anonymous
Anonymous asked in Science & MathematicsChemistry · 8 years ago

How many Nitrate ions are there in 0.42 mol of Ca(NO3)2?

If you know how to calculate this, can you show the formula and equations and all steps needed to find the answer. Thanks

3 Answers

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  • Lexi R
    Lv 7
    8 years ago
    Favorite Answer

    Each Ca(NO3)2 has 2 NO3^- ions

    So moles NO3^- = 2 x moles Ca(NO3)2

    = 2 x 0.42 mol

    = 0.84 mol

    In the same way that 1 dozen of anything = 12 of that anything

    1 mole of anything = 6.022x10^23 of that anything

    this is called avagadros number

    eg

    1 mole atoms = 6.022x10^23 atoms

    1 mole ions = 6.022x10^23 ions

    1 mole eggs = 6.022x10^23 eggs

    So to convert moles of ions to number of ions multiply by 6.022x10^23

    number NO3^- ions = moles NO3^- ions x 6.022x10^23 ions / mole

    = 0.84 mol x 6.022x10^23 ions / mol

    = 5.1x10^23 ions

    Be mindful of what you are asked to give the number of

    for example

    the number of molecules in 0.42 moles of Ca(NO3)2

    = 0.42 mol x 6.022x10^23 molecules/mole

    = 2.5x10^23 molecules

    there are 9 atoms in each Ca(NO3)2 moleule

    So moles atoms = 9 x 0.42 mol

    = 3.78 moles of atoms

    therefore

    number atoms in 0.42 moles Ca(NO3)2 = 3.78 moles atoms x 6.022x10^23 atoms/mol

    = 2.3x10^24 atoms

  • gripp
    Lv 4
    4 years ago

    Ca No3 2

  • halljr
    Lv 4
    4 years ago

    Nitrate Ions

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