# How do i find the velocity of an object oscillating at a certain time?

The velocity of an object in simple harmonic motion is given by v(t)= -(2.98m/s)sin(19.0t + 2.00π), where t is in seconds. What is the first time after t=0.00 s at which the velocity is -0.217m/s?

### 2 Answers

- WoodsmanLv 78 years agoFavorite Answer
-0.217m/s = -2.98m/s * sin(19t + 2π)

sin(19t + 2π) = 0.073

19t + 2π = arcsin(0.073) = 0.073 rads

We can drop the 2π from the LHS, since

sin(Θ + 2π) = sinΘ, so

19t = 0.073 rads

t = 0.003836 s

Check: v(t) = -2.98m/s * sin(19*0.003836 + 2π) = -0.217 m/s √

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