three cards are drawn with replacement, what is the probability of ...?

1) all three will be aces?

2) none of the three will be aces?

3) at least one of them will be an ace?

is it different if it's NOT replaced?

Update:

Dave you are just a great help man around here, thx

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  • 7 years ago
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    Answers are slightly different if not replaced.

    1) If replacement: P(three aces)=(4/52)^3

    2) P(no aces) = (48/52)^3

    3) At least one ace = 1-P(no aces)...see q2 above.

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