Anonymous
Anonymous asked in Science & MathematicsChemistry · 7 years ago

what volume will 40 grams of nitrogen gas occupy at STP?

hint: 1 mole of any gas occupies 22.4L at STP

thank you

2 Answers

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  • Flex
    Lv 5
    7 years ago
    Best Answer

    40 grams of nitrogen gas to moles

    moles = mass / molar mass

    moles of N2 = 40 g / 56 g / mol

    moles of N2 = 0.714 mol

    Volume = moles * molar volume at stp

    Volume = 0.714 * 22.4

    Volume = 15.99 L

    BTW Chubbsss is wrong since he use 14 g/mol as the molar mass of nitrogen gas. Nitrogen gas exists as the form N2. One Nitrogen atom got 14 g/mol. 2 N atoms have 28 g / mol

  • 7 years ago

    40(mass) / 14.01 (molar mass) = 2.855 moles

    2.855 x 22.4 = 63.95 L

    Source(s): Chem minor
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