# 13 cards dealt. Probability of x aces and y clubs?

I know that p(x=4 and y=11) = 0 since if you have 4 aces, you cant have 11 spades as well in the same hand, but is there any relationship that can be written for p(x=i and y=k) for i=1,..,4 and k=1,...,13?

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