# FM radio stations are assigned frequencies every 0.2 , but two nearby stations cannot use adjacent frequencies?

The tuning circuit in an FM radio receiver is a series RLC circuit with a 0.2000 microH inductor.

The receiver is tuned to a station at 103.6MHz . What is the value of the capacitor in the tuning circuit?

FM radio stations are assigned frequencies every 0.2MHz , but two nearby stations cannot use adjacent frequencies. What is the maximum resistance the tuning circuit can have if the peak current at a frequency of 104MHz , the closest frequency that can be used by a nearby station, is to be no more than 0.200% of the peak current at 103.6MHz ? The radio is still tuned to 103.6MHz , and you can assume the two stations have equal strength.

### 2 Answers

- Masked_Rider1101Lv 77 years agoFavorite Answer
ωL=1/ωC

C=1/ω^2L = 1/(2*3.14*103.6*10^6)^2*0.2*10^-6= 11.8[pF]

I don't know of another question.

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- Anonymous7 years ago
Part B

Divide your percentage by 100 and that`s the answer.

- Jonas A5 years agoReport
LMAO it actually works

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