FM radio stations are assigned frequencies every 0.2 , but two nearby stations cannot use adjacent frequencies?
The tuning circuit in an FM radio receiver is a series RLC circuit with a 0.2000 microH inductor.
The receiver is tuned to a station at 103.6MHz . What is the value of the capacitor in the tuning circuit?
FM radio stations are assigned frequencies every 0.2MHz , but two nearby stations cannot use adjacent frequencies. What is the maximum resistance the tuning circuit can have if the peak current at a frequency of 104MHz , the closest frequency that can be used by a nearby station, is to be no more than 0.200% of the peak current at 103.6MHz ? The radio is still tuned to 103.6MHz , and you can assume the two stations have equal strength.
- Masked_Rider1101Lv 77 years agoFavorite Answer
C=1/ω^2L = 1/(2*3.14*103.6*10^6)^2*0.2*10^-6= 11.8[pF]
I don't know of another question.
- Anonymous7 years ago
Divide your percentage by 100 and that`s the answer.