A spring with a spring constant k=100 N/m is stretched by a 20 N force. What is the elastic potential energy o?
A spring with a spring constant k=100 N/m is stretched by a 20 N force. What is the elastic potential energy of the spring?
- ThomasLv 47 years agoBest Answer
Elastic Strain Energy = (1/2)kx^2 where k is the spring constant and x is the extension
to work out the extension do 20N/100Nm^-1 to get 0.2m.
now we have our variables put them into the formula
(1/2) * 100Nm^-1 * 0.2m^2 = 2J while it is a form of energy so the units are obviously Joules we can work it out that they are Joules our units in the equation are Nm^-1 * m^2 which simplifies to Nm which using the formula Work = Force * Distance and given Work has unit Joules then Newtons*Metres = Joules
- 7 years ago