A spring with a spring constant k=100 N/m is stretched by a 20 N force. What is the elastic potential energy o?

A spring with a spring constant k=100 N/m is stretched by a 20 N force. What is the elastic potential energy of the spring?

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  • Thomas
    Lv 4
    7 years ago
    Best Answer

    Elastic Strain Energy = (1/2)kx^2 where k is the spring constant and x is the extension

    to work out the extension do 20N/100Nm^-1 to get 0.2m.

    now we have our variables put them into the formula

    (1/2) * 100Nm^-1 * 0.2m^2 = 2J while it is a form of energy so the units are obviously Joules we can work it out that they are Joules our units in the equation are Nm^-1 * m^2 which simplifies to Nm which using the formula Work = Force * Distance and given Work has unit Joules then Newtons*Metres = Joules

  • 7 years ago

    E=0.5xkx(x)^2

    E=0.5x100x(20/100)^2

    E=2 J

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