Sara asked in Science & MathematicsMathematics · 8 years ago

# Grade 10 math question ?? picking best answer in a hour !!?

A local high school wanted to increase the size of an existing rugby field. The existing dimensions were 30 yards wide by 70 yards long. They wanted to increase the length by 20 yards but keep the shape of the larger field the same as the existing field.

How much would the width have to be increased by to maintain a similar shape?

Select one:

a. 8.57 yards

b. None of these

c. 2.7 yards

d. 7.3 yards

e. 15 yards

Find the approximate distance in kilometres between Vernon, BC

and Port Hardy, BC if a map uses a scale of 1 cm = 40 km and

the distance measured on the map between the two locations is 22 cm.

Select one:

a. 970 km

b. 780 km

c. none of these

d. 880 km

e. 820 km

Find the approximate distance in kilometres between Surrey, BC

and Kamloops, BC if a map

uses a scale of 2 cm = 30 km and

the distance measured on the map is 11 cm.

Select one:

a. none of these

b. 310 km

c. 330 km

d. 270 km

e. 240 km

Relevance
• 8 years ago

Question 1 is a. Question 2 is d. Question 3 is a.

Source(s): Math Major
• 8 years ago

For the first one, to keep the same shape, you have to increase the width by the same

proportion as the length

x/30 = 20/70 or

x/30 = 2/7 just multiply both sides by 30 and get

x = 60/7 = 8.57

For the 2nd one if

1 cm = 40 km then

22 cm = 22(40)km = 880 km

Last one works the same way

2cm = 30 km

You want the left side to be 11 cm, so you have to multiply both sides by 11/2

2 (11/2) cm = 30 (11/2) km

11 cm = 15(11) km = 165 km

• 8 years ago

30/70=x/90

70x=270

x=3.857

b

22x40=880

d

11x15=165

A

• Anonymous
8 years ago

1.)

30/70=x/90

x=2700/70

2.)

1cm=40km

22cm=880km

2.)

2cm=30km

so 1cm=15km

11cm=11*15

= 165km