Calculate the volume in liters for the following gases at STP.?

Calculate the volume in liters for the following gases at STP.

2.09 x 10^22 molecules of methane, CH4 (ans. in 3 sig figs)

V=

3 Answers

Relevance
  • PaulR2
    Lv 7
    6 years ago
    Best Answer

    One mol = 6.02 × 10^23 molecules

    One mol = 22.4L of gas at STP

    2.09 × 10^22 * ( 1 mol / ( 6.02 * 10^23 ) ) = 0.035 mol

    0.035mol * ( 22.4L / 1 mol ) = 0.784L

    Please post chemistry questions in the chemistry section in the future.

  • 6 years ago

    At STP 1 mole of CH4( assuming it obeys the ideal gas law) occupies 22.414 liters.

    Now using Avagadro's Number = 6.022 x10^23 molecules/mol

    You should have (2.09 x10^22/6.022 x 10^23)moles*22.414 liters/mole

    Answer is V = 0.778 L of gas.

    Source(s): chem tutor at times.
  • Ramon
    Lv 7
    6 years ago

    V=(22.4L /1mol)(2.09X10^22 molecules of CH4(1 mol/6.02x10^23 molecules)

    =0.788 liters

Still have questions? Get your answers by asking now.