Calculate the volume in liters for the following gases at STP.?
Calculate the volume in liters for the following gases at STP.
2.09 x 10^22 molecules of methane, CH4 (ans. in 3 sig figs)
- PaulR2Lv 77 years agoFavorite Answer
One mol = 6.02 × 10^23 molecules
One mol = 22.4L of gas at STP
2.09 × 10^22 * ( 1 mol / ( 6.02 * 10^23 ) ) = 0.035 mol
0.035mol * ( 22.4L / 1 mol ) = 0.784L
Please post chemistry questions in the chemistry section in the future.
- Adrian SLv 77 years ago
At STP 1 mole of CH4( assuming it obeys the ideal gas law) occupies 22.414 liters.
Now using Avagadro's Number = 6.022 x10^23 molecules/mol
You should have (2.09 x10^22/6.022 x 10^23)moles*22.414 liters/mole
Answer is V = 0.778 L of gas.Source(s): chem tutor at times.
- RamonLv 77 years ago
V=(22.4L /1mol)(2.09X10^22 molecules of CH4(1 mol/6.02x10^23 molecules)