Calculating volume, at standard pressure and temperature - help?

5.31 x 10^24 of SO2

I'm doing an assignment through distance education and the work they tried to give me to explain the steps I don't quite understand. I don't need the answer, I need the steps! Thanks!

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  • 8 years ago
    Favorite Answer

    I will take this:

    "5.31 x 10^24 of SO2 "

    to mean this:

    5.31 x 10^24 molecules of SO2

    1) determine moles of SO2

    5.31 x 10^24 molecules divided by 6.022 x 10^23 molecules / mole = 8.817668 mole (I'll keep a few extra digits.)

    2) determine volume:

    PV = nRT

    (1.00 atm) (x) = (8.817668 mol) (0.08206 L atm / mol K) (273 K)

    solve for x (round to three sig figs)

    Since we are at STP, we can use molar volume:

    22.414 L/mol times 8.817668 mol = the desired answer

    However, be aware that 22.414 works only at STP. Using PV = nRT is the general solution and works with any values of T and P.

    Source(s): ChemTeam
  • HPV
    Lv 7
    8 years ago

    I'm assuming that you mean 5.31 x 10^24 MOLECULES of SO2 gas.

    1 mole of any substance contains 6.02 x 10^23 particles (atoms or molecules).

    5.31 x 10^24 molecules SO2 x (1 mole SO2 / 6.02 x 10^23 molecules SO2) = 8.82 moles SO2

    At STP (1 atm pressure and 0 degrees C), 1 mole of ANY gas has a volume of 22.4 L.

    8.82 moles SO2 x (22.4 L SO2 / 1 mole SO2) = 198 L

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