Calculating volume, at standard pressure and temperature - help?
5.31 x 10^24 of SO2
I'm doing an assignment through distance education and the work they tried to give me to explain the steps I don't quite understand. I don't need the answer, I need the steps! Thanks!
- ChemTeamLv 78 years agoFavorite Answer
I will take this:
"5.31 x 10^24 of SO2 "
to mean this:
5.31 x 10^24 molecules of SO2
1) determine moles of SO2
5.31 x 10^24 molecules divided by 6.022 x 10^23 molecules / mole = 8.817668 mole (I'll keep a few extra digits.)
2) determine volume:
PV = nRT
(1.00 atm) (x) = (8.817668 mol) (0.08206 L atm / mol K) (273 K)
solve for x (round to three sig figs)
Since we are at STP, we can use molar volume:
22.414 L/mol times 8.817668 mol = the desired answer
However, be aware that 22.414 works only at STP. Using PV = nRT is the general solution and works with any values of T and P.Source(s): ChemTeam
- HPVLv 78 years ago
I'm assuming that you mean 5.31 x 10^24 MOLECULES of SO2 gas.
1 mole of any substance contains 6.02 x 10^23 particles (atoms or molecules).
5.31 x 10^24 molecules SO2 x (1 mole SO2 / 6.02 x 10^23 molecules SO2) = 8.82 moles SO2
At STP (1 atm pressure and 0 degrees C), 1 mole of ANY gas has a volume of 22.4 L.
8.82 moles SO2 x (22.4 L SO2 / 1 mole SO2) = 198 L