# A spring with a spring constant k=440.0 N/m is attached to a mass of m=7 kg and stretched -0.5 m ?!?!?

A spring with a spring constant k=440.0 N/m is attached to a mass of m=7 kg and stretched -0.5 m from its equilibrium position and released.

What is the speed of the block when it is at the equilibrium position?

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- 6 years agoBest Answer
This is a simple conservation of mechanical energy problem

K_f + U_sf = K_i + U_si

1/2 mv^2 + 0 = 0 + 1/2 kx^2

v = root(k/m)*x = 3.96 m/s

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