DISCRETE MATHS HELP!! How many Poker (5-card) hands consist of a.please EXPLAIN!?
How many Poker (5-card) hands consist of a "flush"
(i.e. all cards of the same suit)?
How many Poker (5-card) hands have exactly 3 Aces?
- Elizabeth MLv 76 years agoBest Answer
If you want the number of choices of m different cards chosen from
n different cards it is n!/(m!(n-m)!), where n!=1x2x3x...xn.
1) For each suit you are choosing 5 from 13,
the number of choices =13!/(5!8!)=1287
There are 4 suits so the required number = 1287X4=5148 hands
2) There are 4 aces and 48 not-aces.
You want 3 choices from 4 = 4
with 2 choices from 48 = 48!/(2!46!)=1128
So total =4X1128=4512 hands