A capacitor is made from two 1.90 cm diameter coins separated by a 0.82 mm thick piece of paper (K = 3.70).?

A capacitor is made from two 1.90 cm diameter coins separated by a 0.82 mm thick piece of paper (K = 3.70). A 19.90 V battery is connected to the capacitor.

How much charge is on each coin?

Thank you!!

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  • 6 years ago
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    The capacitance is kappa*epsilon-nought*A/d.

    Here A = pi*r^2 = 2.835 x 10^(-4) m^2

    and d = 8.2 x 10^(-4) m.

    Epsilon-nought = 8.854 x 10^(-12) F/m

    K = 3.70

    Capacitance = 11.33 pF

    Q = VC = (19.90 V)(11.33 pF) = 225 picocoulombs

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