Anonymous
Anonymous asked in Science & MathematicsMathematics · 6 years ago

How do you solve 5^(x+2)-5^(x+1)= 100?

Please show me the steps, I know you have to use logarithms, yet I cant seem to figure out how.

3 Answers

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  • 6 years ago
    Favorite Answer

    Another method

    5^(x+2)-5^(x+1)= 100?

    5^x*5^2 - 5^x*5 = 100

    5^x[5^2 - 5] = 100

    5^x * 20 = 100

    5^x = 5

    x = 1

  • 6 years ago

    5^(x+2)-5^(x+1)= 100

    5^(x + 1)(5) - 5^(x + 1)(1) = 100

    5^(x + 1)(5 - 1) = 100

    5^(x + 1)(4) = 100

    5^(x + 1) = 25

    5^(x + 1) = 5^2

    x + 1 = 2

    x = 1

  • Karl
    Lv 6
    6 years ago

    5^(x+2) - 5^(x+1)= 100

    5^(x+1)(5 - 1) = 4* 5² , divide by 4

    5^(x+1) = 5²

    x+ 1 = 2

    x = 1

    ====

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