Central limit theorem question?
According the International Atomic Energy Agency, electricity per-capita consumption in Canada is 16,939 kwh in 2002. A random sample of 53 households is monitored for one year to determine electricity usage. If the population standard deviation of annual usage is 3,500 kwh, what is the probability that the sample mean will be each of the following?
Less than 16,000 kwh
Less than 15,000 kwh
As population mean = 16939 n=53 SD=3500 sample SD=480.76197
I got p(z<16000)=-1.95 0.4744 0.5-04744=0.02560
but it is not correct
and if the sample mean is less than 15000, z score= -4.03318 the number is not on the data.
How can I solve this question? help me please
- 6 years agoFavorite Answer
Xbar < 16000;
so Z score = [16000 - 16939] / 480.762 = - 1.95
P(Z<= -1.95) = 0.02559
Your answers are correct.Source(s): Google Tutorteddy.com for more Question and Answers…
- cidyahLv 76 years ago
First is correct.
Second is correct.
P( z < -4.03318) = 0.0000 (almost 0)
If you want an exact answer:
P( z < -4.03318) = 2.75135 x 10^(-5) ( Excel)