# A grasshopper can jump a maximum horizontal distance of 40 cm.It spends negligible time on ground, then its speed along the plane will be?

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- WhomeLv 75 years agoFavorite Answer
If we assume g = 9.8 m/s² and that air resistance will be negligible and the surface traveled over is horizontal, then we know the launch angle will be 45° and the initial horizontal and vertical velocities will be equal.

as speed is distance over time

The horizontal velocity will be

v = d/t

the time taken for the initial vertical velocity to drop to zero is

t' = v/g

and each leap will take twice that long

t = 2t' = 2v/g

plugging this time value into our original velocity equation for one leap

v = d/(2v/g)

v = dg/2v

v² = dg/2

v = √(dg/2)

v = √(0.4(9.8)/2)

v = 1.4 m/s

I hope this helped.

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- Anonymous5 years ago
2 points thanks

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