A grasshopper can jump a maximum horizontal distance of 40 cm.It spends negligible time on ground, then its speed along the plane will be?
- WhomeLv 75 years agoFavorite Answer
If we assume g = 9.8 m/s² and that air resistance will be negligible and the surface traveled over is horizontal, then we know the launch angle will be 45° and the initial horizontal and vertical velocities will be equal.
as speed is distance over time
The horizontal velocity will be
v = d/t
the time taken for the initial vertical velocity to drop to zero is
t' = v/g
and each leap will take twice that long
t = 2t' = 2v/g
plugging this time value into our original velocity equation for one leap
v = d/(2v/g)
v = dg/2v
v² = dg/2
v = √(dg/2)
v = √(0.4(9.8)/2)
v = 1.4 m/s
I hope this helped.
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- Anonymous5 years ago
2 points thanks