Please factor 9y^2 + 12y − 5 = 0?

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  • DWRead
    Lv 7
    4 years ago

    9y² + 12y - 5 = 0

    Use quadratic formula

    y = [-12 ± √(12² – 4·9(-5))] / [2·9]

     = [-12 ± √324] / 18

     = [-12 ± 18] /18

     = -1⅔, ⅓

    9y² + 12y - 5 = 9(x+1⅔)(x-⅓) = (3x+5)(3x-1)

  • 4 years ago

    Splitting the middle term, 9y^2 + 15y - 3y - 5 = 0

    => 3y(3y + 5) - (3y + 5) = 0

    ==> (3y + 5)(3y - 1) = 0

  • 4 years ago

    THANKS!!

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