Anonymous
Anonymous asked in Science & MathematicsPhysics · 3 years ago

A 44.2 g pinball starts at the top of a frictionless pinball table inclined at 45.0°?

A 44.2 g pinball starts at the top of a frictionless pinball table inclined at 45.0°. If the ball is released and the spring at the bottom is compressed 0.0500 m and has a spring constant of k = 24.5 N/m, how far back up the pinball table will the pinball travel before rolling back down again?

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  • 3 years ago
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    Change in energy = 0

    Change in GPE + Change in SPE = 0

    M*g*(hf - hi) + 1/2*k*(xf^2 - xi^2) = 0

    Eliminate some variables

    Hf-hi = h

    Xf = 0

    So,

    M*g*h - 1/2*k*xi^2 = 0

    Solve for h

    h = (k*xi^2)/(2*m*g)

    Finally, the height is a component of length.

    H = L*sin (theta)

    Plug in and solve for L

    L = (k*xi^2)/(2*m*g*sin (theta))

    Now plug in numbers

    L = 0.100 m

    Thats what I got

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