A probe then entered the orbit around the comet at a distance of 30 km. The comet was found to have a mass of 1.0×10^13kg.?
What was the orbital period of the probe around the comet, in earth days?
- RealProLv 72 years agoFavorite Answer
In a circular orbit, at any point the centripetal force is provided by the gravitational attraction between the two objects.
GMm / r^2 = mv^2 / r
G = universal gravitational constant
M = mass of comet
m = mass of probe
r = distance of prob from centre of comet
v = speed of probe
But v = 2pi * r / T where T is period of orbit
GM / r^2 = (2pi * r / T)^2 / r
Solve for T
T = 2pi * sqrt(r^3 / (GM))
Plug in. The raw values provided will yield period in seconds which you can convert to days by dividing with 86,400 s/d.
- somegLv 62 years ago
You just made that up. That didn't really happen.
- GrundoonLv 72 years ago
How the hell would something orbit a comet? The gravitational field would be minuscule.