# A probe then entered the orbit around the comet at a distance of 30 km. The comet was found to have a mass of 1.0×10^13kg.?

Update:

What was the orbital period of the probe around the comet, in earth days?

### 3 Answers

Relevance

- RealProLv 72 years agoFavorite Answer
In a circular orbit, at any point the centripetal force is provided by the gravitational attraction between the two objects.

GMm / r^2 = mv^2 / r

G = universal gravitational constant

M = mass of comet

m = mass of probe

r = distance of prob from centre of comet

v = speed of probe

But v = 2pi * r / T where T is period of orbit

So rewrite

GM / r^2 = (2pi * r / T)^2 / r

Solve for T

T = 2pi * sqrt(r^3 / (GM))

Plug in. The raw values provided will yield period in seconds which you can convert to days by dividing with 86,400 s/d.

- GrundoonLv 72 years ago
How the hell would something orbit a comet? The gravitational field would be minuscule.

Still have questions? Get your answers by asking now.