# What magnitude force is the piston applying?

The towers holding small wind turbines are often raised and lowered for easy servicing of the turbine. (Figure 1) shows a 1000 kg wind turbine mounted on the end of a 24-m-long, 500 kg tower that connects to a support column at a pivot. A piston connected 3.0 m from the pivot applies the force needed to raise or lower the tower. At the instant shown, the wind turbine is being raised at a very slow, constant speed.

### 2 Answers

- NCSLv 72 years agoFavorite Answer
Assuming

i) the tower is at 10º from horizontal, and

ii) the piston is at 75º from the tower, and

iii) the ratio of piston-to-pivot/turbine-to-pivot is 3.0/24,

then for rotational equilibrium ("slow, constant speed"), we need

ΣM = 0 = F*(3.0/24)*cos10º*sin75º - 1000kg*9.8m/s²*cos10º

solves to

F = 81 000 N

to two significant digits.

If your distances or angles differ, plugging in your values should work.

I used the diagram at the link below.

Hope this helps!