Need some help on this physics momentum question?

At the centre of a circular ice rink, a 88.0 kg ice skater moving 1.95 m/s north hits and grabs onto a 51.0 kg ice skater who had been traveling west at 4.35 m/s. If the skaters hold onto each other and the rink has a 22.0 m diameter, what is the amount of time for the skaters to reach the edge of the rink?

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  • Whome
    Lv 7
    2 years ago
    Favorite Answer

    North momentum

    88.0(1.95) + 51.0(0) = (88.0 + 51.0)vy

    vy = 1.2345 m/s

    West momentum

    88.0(0) + 51.0(4.35) = (88.0 + 51.0)vx

    vx = 1.596 m/s

    velocity after collision

    v = √(1.596² + 1.2345²)

    v = 2.0177...

    v = 2.02 m/s

    t = d/v

    t = (22.0 / 2) / 2.02

    t = 5.4515...

    t = 5.45 s

    I hope this helps.

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  • Janet
    Lv 7
    2 years ago

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