Mihai asked in Science & MathematicsPhysics · 2 years ago

# Need some help on this physics momentum question?

At the centre of a circular ice rink, a 88.0 kg ice skater moving 1.95 m/s north hits and grabs onto a 51.0 kg ice skater who had been traveling west at 4.35 m/s. If the skaters hold onto each other and the rink has a 22.0 m diameter, what is the amount of time for the skaters to reach the edge of the rink?

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• Whome
Lv 7
2 years ago
Favorite Answer

North momentum

88.0(1.95) + 51.0(0) = (88.0 + 51.0)vy

vy = 1.2345 m/s

West momentum

88.0(0) + 51.0(4.35) = (88.0 + 51.0)vx

vx = 1.596 m/s

velocity after collision

v = √(1.596² + 1.2345²)

v = 2.0177...

v = 2.02 m/s

t = d/v

t = (22.0 / 2) / 2.02

t = 5.4515...

t = 5.45 s

I hope this helps.

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• Janet
Lv 7
2 years ago

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